x^2-(4x/5)+20=(101/25)

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Solution for x^2-(4x/5)+20=(101/25) equation:



x^2-(4x/5)+20=(101/25)
We move all terms to the left:
x^2-(4x/5)+20-((101/25))=0
We add all the numbers together, and all the variables
x^2-(+4x/5)+20-((+101/25))=0
We get rid of parentheses
x^2-4x/5+20-((+101/25))=0
We calculate fractions
x^2+(-100x^2)/()+20+()/()=0
We add all the numbers together, and all the variables
x^2+(-100x^2)/()+21=0
We multiply all the terms by the denominator
(-100x^2)+x^2*()+21*()=0
We add all the numbers together, and all the variables
(-100x^2)+x^2*()=0
We get rid of parentheses
-100x^2+x^2*()=0

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